-2a^2+72a=0

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Solution for -2a^2+72a=0 equation:



-2a^2+72a=0
a = -2; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-2)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-2}=\frac{-144}{-4} =+36 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-2}=\frac{0}{-4} =0 $

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